perlukan bantuan untuk coding php

paranoidz · #1 (**permalink**) 05-05-2004, 09:00 AM

aku ade buat satu webbase system cam helpdesk...aku ingin buat password tapi coding aku tak berjalan lancar la...boleh sesiapa bantu aku untuk buat coding tuk password.

ade sesiapa boleh bantu aku buat coding untuk search cam search nama, or barang dalam webbase aku nie...

lcf · #2 (**permalink**) 05-05-2004, 09:53 AM

wat? sorry, I do not understand your language.

In your check.php, you should get the submited form data first. use $variableName = $_POST['FIELD']

paranoidz · #3 (**permalink**) 05-05-2004, 09:58 AM

do you have any script that written properly cause i'm new in php...

lcf · #4 (**permalink**) 05-05-2004, 02:13 PM

no, sorry.
we are here to help you, not here to write code for you.

paranoidz · #5 (**permalink**) 05-05-2004, 09:01 PM

ok i repaired my script first then i submit here

paranoidz · #6 (**permalink**) 07-05-2004, 04:32 PM

Quote:

<body topmargin="0" leftmargin="0">
<form name="password" method="post" action="<?echo $PHP_SELF?>">
<table width="300" border="0" align="center" cellpadding="0" cellspacing="0" class="border">
<tr>
<td width="400" class="text"><div align="center"></div></td>
</tr>
<tr>
<td class="text"><table width="250" border="0" cellpadding="0" cellspacing="0" class="text">
<tr>
<td width="94"><div align="right">username</div></td>
<td width="9">: </td>
<td width="120"><input name="username" type="text" id="username" maxlength="12" border="0"></td>
</tr>
<tr>
<td><div align="right">password</div></td>
<td>: </td>
<td><input name="password" type="password" id="password" maxlength="8"></td>
</tr>
<tr>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td colspan="3"><div align="right">
<input type="submit" name="Submit" value="Submit" border="0">
</div></td>
</tr>
<tr>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td colspan="3"><div align="center">forgot password contact nazrin</div></td>
</tr>
</table>
<div align="left"></div>
<div align="center"></div></td>
</tr>
</table>
</form>
<?php
if ($submit) {
$db=mysql_connect("localhost","sreport") or die ("connection problem");
mysql_select_db("sreport",$db) or die ("cant connect to database");
$result=mysql_query("select * from user where name='$username'",$db) or die ("database not found");
while ($row=mysql_fetch_array($result)) {
if ($row["password"]==$password) {
printf("Successfully Logged In!<a href="report/report.php?">Click Here</a>");
}
}
}
?>
</body>
</html>

Parse error: parse error in C:\apache\htdocs\sreport\users\users.php on line 223...
the error refer hereprintf("Successfully Logged In!<a href="report/report.php?">Click Here</a>");

MHR · #7 (**permalink**) 07-05-2004, 07:34 PM

your script is screwed if the server enabled register_globals
*laughs*

hafizuddin · #8 (**permalink**) 07-05-2004, 10:49 PM

maybe u need to escape the double quote eh

, like this

printf("Successfully Logged In!<a href=\"report/report.php?\">Click Here</a>");

paranoidz · #9 (**permalink**) 10-05-2004, 05:25 PM

<?php
function print_form() {
?>
<form action="chk_pass.php3" method="post">
<h3>Please Login</h3>
Username : <input type="text" name="user_name">
Password : <input type="password" name="user_pass">
<input type="submit" name="submit" value="login">
</form>
<?
}

if(isset($submit));

if(!$db = mysql_connect("localhost","root")):
print("<h1>Database Connection Failed</h1>\n");
else:
mysql_select_db("users",$db);
endif;

$sql = "select * from users where user_name = '$user_name'";
$result = mysql_query($sql);
$row_count = mysql_num_rows($result);
if($row_count == 0):
?>
<h3>Wrong Username</h3>
<?
print_form();
else:
$row = mysql_fetch_array($result);
if($password != $row["user_pass"]):
?>
<h3>Invalid Password</h3>
<?
print_form();
else:
?>
<h3>Password Accepted</h3>
<?
endif;
endif;
else: <---------------------error asyik kat sini...
print_form();
endif;
?>

aku modified script tu kasik lowert skit...n dapat error nie...

hafizuddin · #10 (**permalink**) 10-05-2004, 09:01 PM

kat if(isset($submit)); tu hujung dia tanda ni ; ke : ???

paranoidz · #11 (**permalink**) 12-05-2004, 10:35 AM

PHP Code:


			
if ($_POST[user] && $_POST[pass]) {  

$result = mysql_query("select * from users where user_name='$_POST[user]");    

$row = mysql_fetch_array($result);    

if ($row[id] > 0) {     

setcookie ("user", md5($user_data[username]));      

setcookie ("pass", md5($user_data[password])); 

header("Location: users.php");    }

 else 

{ $login_error= true; }   }

Warning: Supplied argument is not a valid MySQL result resource in c:\apache\htdocs\sreport\users\users.php on line 26

camner nie ye

lcf · #12 (**permalink**) 12-05-2004, 12:10 PM

replace:

PHP Code:


			
$result = mysql_query("select * from users where user_name='$_POST[user]");

with:

PHP Code:


			
$result = mysql_query("select * from users where user_name='" . $_POST[user] . "'");

paranoidz · #13 (**permalink**) 12-05-2004, 12:49 PM

PHP Code:


			
<?php

$db_username = "ayin"; 

$db_password = "mypass"; 

$db_hostname = "localhost";     

$db_connect = mysql_connect($db_hostname, $db_username, $db_password)or die("Unable to connect to MySQL"); 

$db_select = mysql_select_db("sreport", $db_connect)or die("Unable to select test"); 

//additional functionality here 

echo "You have successfully connected to MySQL!"; 

mysql_close($db_connect);



//$username = 'admin';  

//$password = 'password';



//current time

$time=time();



//logout

if($logout == true){

setcookie("user",md5($_POST[user]),$time-3200);

setcookie("pass",md5($_POST[pass]),$time-3200);

header("location:users.php");

}



//mysql validate

if ($_POST[user] && $_POST[pass]) {

$result = mysql_query("select * from users where user_name='" . $_POST[user] . "'");

 $row = mysql_fetch_array($result); 

 if ($row[id] > 0) { 

  setcookie ("user", md5($user_data[username]));  

  setcookie ("pass", md5($user_data[password]));  

  header("Location: users.php"); 

 } else { $login_error= true; } 

}

still same problem la...anybody can help me...

lcf · #14 (**permalink**) 12-05-2004, 08:08 PM

Try change all
$_POST[pass] to $_POST["pass"]
$_POST[user] to $_POST["user"]
$user_data[username] to $user_data["username"]
$user_data[password] to $user_data["password"]

paranoidz · #15 (**permalink**) 12-05-2004, 08:49 PM

did u mean like this...i try 1st...if still cannot i give my other script but i need to do a cookies for this script n it did not work as i wanted...tomorrow i post it here...

PHP Code:


			
<?php

$db_username = "ayin"; 

$db_password = "mypass"; 

$db_hostname = "localhost";     

$db_connect = mysql_connect($db_hostname, $db_username, $db_password)or die("Unable to connect to MySQL"); 

$db_select = mysql_select_db("sreport",